2+6x+4x^2=0

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Solution for 2+6x+4x^2=0 equation: 



2+6x+4x^2=0

a = 4; b = 6; c = +2;
Δ = b2-4ac
Δ = 62-4·4·2
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2}{2*4}=\frac{-8}{8}
=-1
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2}{2*4}=\frac{-4}{8}
=-1/2
$

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